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20k-7k^2=0
a = -7; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-7)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-7}=\frac{-40}{-14} =2+6/7 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-7}=\frac{0}{-14} =0 $
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